Switch Case Statement
Use a switch/case statement in variables environments to make sure your variables satisfy specific constraints
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | \begin{variables}
\randint{dice}{1}{3}
\begin{switch}
\begin{case}{dice=1}
<variable definitions>
\end{case}
\begin{case}{dice=2}
<variable definitions>
\end{case}
...
\begin{default}
<variable definitions>
\end{default}
\end{switch}
\end{variables}
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Every variable in a switch environment must have a default definition, but not a definition for every
single case environment. (see example below)
There is no limitation on how many case environments you can use inside a switch environment.
The default environment though is obligatory!
You can use switch/case statements globally and on question level.
Never use switch/case statements in combination with \randadjustIf. It is meant as an alternative.
Example 1
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 | \begin{variables}
\randint{a}{1}{5}
\function{f0}{10*a}
\begin{switch}
\begin{case}{a>3}
\number{c}{3}
\randrat{d}{1}{2}{3}{7}
\drawFromSet{m}{1,2,3}
\function{f}{2*a}
\derivative{g}{3x^2+sqrt(x)}{x}
\substitute{h}{sqrt(y)}{y}{g}
\string{s}{case 1}
\end{case}
\begin{case}{a=3}
\number{c}{5}
\end{case}
\begin{default}
\randint{c}{1}{10}
\randrat{d}{-2}{-1}{3}{7}
\drawFromSet{m}{-1,-2,-3}
\function{f}{-2*a}
\derivative{g}{-3x^2+sqrt(x)}{x}
\substitute{h}{sqrt(y)}{y}{g}
\string{s}{default case}
\end{default}
\end{switch}
\end{variables}
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Example 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 | \begin{problem}
\begin{variables}
\randint[Z]{s}{-1}{1}
\begin{switch}
\begin{case}{s>0}
\string{s_equation}{
\begin{equation*}
\int \cos(x)\cdot e^x\,dx.
\end{equation*}
}
\end{case}
\begin{default}
\string{s_equation}{
\begin{equation*}
\int \sin(x)\cdot e^x\,dx.
\end{equation*}
}
\end{default}
\end{switch}
\function{f1}{1/2*exp(x)*(sin(x)+s*cos(x))}
\end{variables}
\begin{question}\type{input.function}
\text{
Lösen Sie das folgende unbestimmte Integral mittels partieller Integration
\\
\var{s_equation}
\\
Die Lösung lautet $F(x)= $ \ansref $+\ c$.
}
\begin{answer}
\solution{f1}
\inputAsFunction{x}{A0}
\checkFuncForZero{A0-f1}{-1}{1}{10}
\end{answer}
\end{question}
\end{problem}
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