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The automatic correction of generic TeX problems can take into account consecutive errors. This feature is only

available for questions of type `input.number`

or `input.function`

.

Consider a problem with several questions, all of them of type `input.number`

or type `input.function`

.

Assume the solution of the n-th question depends on the solution of the m-th question for some question numbers $$m$$,$$n$$

with $$m < n$$. Say the student's solution of the m-th question was wrong. Then the student used a wrong input for the

n-th question. Assume that, apart from starting with a wrong input, the student solved the n-th question correctly.

This is what we call a *consecutive error*.

Taking into account consecutive errors means the student doesn't get the points for the m-th question, but the solution

of the n-th question is counted as correct and the points are awarded.

Taking into account consecutive errors works as follows. The questions are corrected one after the other.

For each question, the following happens:

- First, the question is corrected normally, meaning the student's solution is compared to the correct solution.
- If the student's solution coincide with the correct solution, everything is ok and the correction proceeds to the

next question. - Otherwise, the correction of this question is repeated with certain variables bound to student answers of previous

questions. This is called*conditional correction.*Which variable is bound to which answer is controlled by the author

using the`\earlierAnswer`

command described below. - The score resulting from the conditional correction is compared to that of the normal correction. The correction

with the higher score counts.

The `\earlierAnswer`

command has the following form:

`\earlierAnswer{VARIABLE}{QUESTION_NUMBER,ANSWER_NUMBER}`

where `VARIABLE`

is the name of the variable **defined on global (not question or answer) level**, `QUESTION_NUMBER`

the number of the question and `ANSWER_NUMBER`

the number of the answer.

If another variable depends on a variable that is referenced in `\earlierAnswer`, the
dependent variable must also be defined in the global (and not in a question/answer) variable environment.

The answer number and the comma before it can be omitted:

`\earlierAnswer{VARIABLE}{QUESTION_NUMBER}`

In that case, the answer number defaults to 1.

The `\earlierAnswer`

command is only allowed in the "variables" environment of a question.

Do not use the command

`\earlierAnswer`

to refer to an earlier question in a problem that has
`\randomquestionpool`

enabled! Problems with random question pools can only use `\earlierAnswer`

for subtasks within the same question, by using the value -1 for the question number.Below is a complete example of a problem. The problem is trivial: a random number Q is given, and the student has to

compute $$x = Q + 1$$ in the first question, $$y = x + 1$$ in the second, and $$z = y + 1$$ in the third. The second

and third question depend on the solutions of previous questions. To take this into account, we added `\earlierAnswer`

commands to bind variables to earlier answers. In the second question, for example, we bound x to the first answer of

question 1.

1234567891011121314151617181920212223242526272829303132333435363738394041424344454647484950515253545556575859606162 `\begin{problem}`

` `

`\begin{variables}`

` `

`\randint{Q}{-4}{4}`

` `

`\function{x}{Q+1} `

` `

`\function{y}{x+1} `

` `

`\function{z}{y+1} `

` `

`\end{variables}`

` `

`\begin{question}`

` `

`\text{\textbf{Step 1}\\ \textit{Let Q = $\var{Q}$. Compute x = Q + 1:}}`

` `

`\explanation{Simply add one}`

` `

`\type{input.number}`

` `

`\precision{3}`

` `

`\field{real}`

` `

`\begin{answer}`

` `

`\text{ x = }`

` `

`\solution{x}`

` `

`\end{answer}`

` `

`\end{question}`

` `

`\begin{question}`

` `

`\begin{variables}`

` `

`\earlierAnswer{x}{1,1}`

` `

`\end{variables}`

` `

`\text{\textbf{Step 2}\\ \textit{Compute y = x + 1:}}`

` `

`\explanation{Simply add one}`

` `

`\type{input.number}`

` `

`\precision{3}`

` `

`\field{real}`

` `

`\begin{answer}`

` `

`\text{ y = }`

` `

`\solution{y}`

` `

`\end{answer}`

` `

`\end{question}`

` `

`\begin{question}`

` `

`\begin{variables}`

` `

`\earlierAnswer{x}{1,1}`

` `

`\earlierAnswer{y}{2,1}`

` `

`\end{variables}`

` `

`\text{\textbf{Step 3}\\ \textit{Compute z = y + 1:}}`

` `

`\explanation{Simply add one}`

` `

`\type{input.number}`

` `

`\precision{3}`

` `

`\field{real}`

` `

`\begin{answer}`

` `

`\text{ z = }`

` `

`\solution{z}`

` `

`\end{answer}`

` `

`\end{question}`

`\end{problem}`

You can also set the `QUESTION_NUMBER`

to -1 to refer to a previous answer in the *same* question:

`\earlierAnswer{VARIABLE}{-1,ANSWER_NUMBER}`

When you use `\randomquestionpool`

(see Randomquestionpool) at the begin of

a problem to make a selection, this is the only case of `\earlierAnswer`

that you can use.

**Warning**:

If you use `\earlierAnswer{VARIABLE}{-1,ANSWER_NUMBER}`

, be aware of the correction procedure described above.

*Wrong use*:

123456789101112131415161718192021222324252627 `\begin{problem}`

` `

`\begin{variables}`

` `

`\randint{Q}{-4}{4}`

` `

`\function{x}{Q+1} `

` `

`\function{y}{x+1} `

` `

`\end{variables}`

` `

`\begin{question}`

` `

`\begin{variables}`

` `

`\earlierAnswer{x}{-1,1}`

` `

`\end{variables}`

` `

`\text{Let Q = $\var{Q}$.}`

` `

`\type{input.number}`

` `

`\begin{answer}`

` `

`\text{Compute x = Q + 1:}`

` `

`\solution{x}`

` `

`\end{answer}`

` `

`\begin{answer}`

` `

`\text{Compute y = x + 1:}`

` `

`\solution{y}`

` `

`\end{answer} `

` `

`\end{question}`

`\end{problem}`

In this line of code, the student will always get full score for the first answer. Indeed, if

the answer is wrong, the correction will be repeated with `x`

being the student's first answer,

and so evaluate the first answer as conditionally correct.

The correct way is given by using a *copy* of the variable `x`

:

12345678910111213141516171819202122232425262728 `\begin{problem}`

` `

`\begin{variables}`

` `

`\randint{Q}{-4}{4}`

` `

`\function{x}{Q+1}`

` `

`\function{xc}{x} `

` `

`\function{y}{xc+1} `

` `

`\end{variables}`

` `

`\begin{question}`

` `

`\begin{variables}`

` `

`\earlierAnswer{xc}{-1,1}`

` `

`\end{variables}`

` `

`\text{Let Q = $\var{Q}$.}`

` `

`\type{input.number}`

` `

`\begin{answer}`

` `

`\text{Compute x = Q + 1:}`

` `

`\solution{x}`

` `

`\end{answer}`

` `

`\begin{answer}`

` `

`\text{Compute y = x + 1:}`

` `

`\solution{y}`

` `

`\end{answer} `

` `

`\end{question}`

`\end{problem}`

Now the solution `x`

of the first answer is not affected by the `\earlierAnswer`

-command,

but the solution `y`

of the second answer will.

By default the user obtains the same amount of points for every correct answer within a problem.

An exception is the case where an answer is not evaluated directly (compare the example for CheckFunctionForZero ).

This default can be changed by using the `\score`

-command.

123456789101112131415161718192021222324252627282930313233 `\usepackage{mumie.genericproblem}`

`\title{Different Score Weights Per Answer}`

`\begin{problem}`

` `

`\begin{variables}`

` `

`\number{a}{1}`

` `

`\number{b}{2}`

` `

`\end{variables}`

`\begin{question}`

` `

`\text{1 or 2?}`

` `

`\explanation{}`

` `

`\type{input.number}`

` `

`\field{real}`

` `

`\begin{answer}`

` `

`\text{$1\cdot 1=$}`

` `

`\solution{a}`

` `

`\end{answer}`

` `

`\begin{answer}`

` `

`\text{$1\cdot 2=$}`

` `

`\solution{b}`

` `

`\score{2} % default score is 1`

` `

`\end{answer}`

`\end{question}`

`\end{problem}`

In the example above, the second answer is given the score weight 2.

Hence, if the total amount of points for the problem is 6, a correct first answer gives 2 points, a correct second answer 4 points.

This also works with answers in multiple questions.

Remark: The total amount of points for a problem is set in the "Settings" of a course in which it is used, and can change from course to course.

Updated by **Michael Heimann**, **5 months ago **– d93e379